Solve 2\Xd7(\Xd7+4)=(\Xd7-3)(\Xd7-3)

Solve 2×(×+4)=(×-3)(×-3)

 

Answer:

2x(x+4)=(x−3)(x−3)

2x²+8x=x²−6x+9

x²+14x−9=0

x=−b±√²−4ac/2a

x=−(14)±√(14)²−4(1)(−9)/2(1)

x=−14±√232/2

x=−7+√58 or x=−7−√58

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